To get from C(-1, 4) to C'(-3,0), we must subtract the x value by -2. This gets us -3 (-1-2=-3). To get from 4 to 0, we must subtract the y-values by 4. This gets us a translation of 2 left and 4 down or T₋₂,₋₄
Answer:
x=4+√73 or x=4−√73
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
x^2−8x−48=9
Step 2: Add 48 to both sides.
x^2−8x−48+48=9+48
x^2−8x=57
Step 3: The coefficient of -8x is -8. Let b=-8. Then we need to add (b/2)^2=16 to both sides to complete the square.
Add 16 to both sides.
x^2−8x+16=57+16
x^2−8x+16=73
Step 4: Factor left side.
(x−4)^2=73
Step 5: Take the square root.
x−4=±√73
Step 6: Add 4 to both sides.
x−4+4=4±√73
x=4±√73
x=4+√73 or x=4−√73
Answer:
x=4+√73 or x=4−√73
If this answer helped you, I would greatly appreciate it if you gave me brainliest :D.
To solve this problem you must apply a theorem called: Intersecting secant theorem. The proccedure is shown below:
1) For the figure shown on the left:
(5)(x+5)=(6)(4+6)
5x+25=60
5x=60-25
x=35/5
x=7
2) For the figure shown on the right:
(3)(3+5)=(4)(x+4)
24=4x+16
24-16=4x
8=4x
8/4=x
x=2
C is the right answer I think