What’s the vertex of the graph of the function y=x^2-8x+12

Mathematics

1 answer:

myrzilka [38]3 years ago

6 0

Answer:

The vertex is 4

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How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)

SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

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Determine the intercepts of the line that correspond to the following table of values.

Dahasolnce [82]

We know that
to find the equation of a line i need two points

let
point A-----> (-21,10)
point B-----> (-28,14)

step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7

step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2

step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5

the x intercept is (-3.5,0)

step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)

the answers are
the x intercept is (-3.5,0)
the y intercept is (0,-2)

see the attached figure