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Paha777 [63]
3 years ago
8

Abigail has a cylindrical candle mold with the dimensions shown. If Abigail has a rectangular block of wax measuring 15 cm by 12

cm by 18 cm, about how many candles can she make after melting the block of wax? Round to the nearest tenth.

Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Find the volume of the candle using the formula for volume of a cylinder:

V = PI x r^2 x h = 3.14 x 3.4^2 x 6 = 217.79 cubic cm. Round to 217.8

Find the volume of the block: V = l x w x h = 15 x 12 x 18 = 3,240 cubic cm.

Now divide the volume of the block by the volume of a candle:

3240 / 217.8 = 14.88

Round to the nearest tenth = 14.9 candles.

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Help please i’ll really appreciate it
maw [93]

Answer:

radius is 4 height is 10 volume is 167.55

Step-by-step explanation:

3 0
3 years ago
A circle with area \blue{9\pi}9πstart color #6495ed, 9, pi, end color #6495ed has a sector with a central angle of \purple{60^\c
Liono4ka [1.6K]

Answer:

The area of the sector is 3pi/2

Step-by-step explanation:

A sector is that part of a circle bounded by 2 radii and an arc

The circle has an area of 9 pi with a central angle of 60 degrees.

Now the area of the sector is pretty much straight forward to calculate. Since it is a circle, the total angle we have is 360.

Now the sector subtends an angle of 60 degrees at the centre. What this means is that the sector is exactly 1/6 of the circle. meaning that cutting the circle into 6 slices will give the sector.

Thus, the area of the sector is one-sixth the area of the circle.

The area of the sector is thus 1/6 * 9pi = 9pi/6 = 3pi/2 or 3/2 pi

6 0
3 years ago
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x. 
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
= 2x (27 - 3x^2) 
= 54x - 6x^3 
For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

d²A/dx² = - 36x < 0 for x = √3 
=> maximum area 
= 54(√3) - 6(√3)^3 
= 54√3 - 18√3 
= 36√3. 
4 0
3 years ago
Answer the question in the picture
Schach [20]

The area of the semicircle is A = 1187.9 cm².

<h3>What is the area of a circle?</h3>

The area of a circle with a radius of r is A = πr².

Given that, the diameter of the semicircle is 55 cm.

The radius of the semicircle is,

r = 55/2

The area of a semicircle is given by,

A = (1/2)πr²

Substitute the values,

A = (1/2)π(55/2)²

A = 1187.9

Hence, the area of the semicircle is A = 1187.9 cm².

Learn more about the area of a circle:

brainly.com/question/22964077

#SPJ1

6 0
1 year ago
5. Write each number in another form.
sukhopar [10]
Your answer would be c
7 0
3 years ago
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