Answer:
A. $707. 88
B. $12,033.96
Step-by-step explanation:
A. 58.99 × 12 = 707.88
B. 707.88 × 17 = 12,033.96
Hope this helps!
She spent 5% of her money
Answer:
* The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.
* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.
Step-by-step explanation:
Recall that a penny is a money unit. It is created/produced, just like any other commodity. As a matter of fact, almost all types of money or currency are manufactured; with different materials ranging from paper to solid metals.
A group of pennies made in a certain year are weighed. The variable of interest here is weight of a penny.
The mean weight of all selected pennies is approximately 2.5grams.
The standard deviation of this mean value is 0.02grams.
In this context,
* The mean (a measure of central tendency) weight value is the average of the weights of all pennies in the study.
* The standard deviation (a measure of variability or dispersion) describes the lowest and highest any individual penny weight can be. Subtracting 0.02g from the mean, you get the lowest penny weight in the group.
Likewise, adding 0.02g to the mean, you get the highest penny weight in the group.
Hence, the weight of each penny in this study, falls within
[2.48grams - 2.52grams]
Answer:
la respuesta esta abajo
Step-by-step explanation:
a) Sea x el número del artículo x mientras que y representa el número del artículo y.
Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:
2x + 5y ≤ 40
b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.
c) Para 10 unidades de X y 5 unidades de y:
2 (10) + 5 (5) = 45> 40
Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.
