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valentinak56 [21]
3 years ago
8

(QUICKLY!) Describe two methods that can be used to find the area of the composite figure.

Mathematics
2 answers:
ryzh [129]3 years ago
4 0

Answer:4 squares or a rectangle and a square

Step-by-step explanation:

Alona [7]3 years ago
3 0
Rectangle and square is one
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Find the area of the shape shown below.
maw [93]

Answer:

The area is 28.

Step-by-step explanation:

Visualize the rectangle as 2 split squares.

The top square is easily 4x4, so the area of that part is 16.

Now visualize the bottom square as two rectangles.

To find the area of the dented side, you would use the equation of finding the area of a triangle, a=(w x h)\frac{1}{2} because the dented side is actually just one half of the rectangle on the other side.

Since it is the same height as the top square, but is 2 in width, it would be written as a=(2 x 4)\frac{1}{2} . So the area of that part is 4, and the area of the other rectangle would be just 2 x 4 so it is 8.

Totaling these numbers, you get the area of the full rectangle.

8 0
4 years ago
Read 2 more answers
Two angles from a linear pair. the measure of one angle is 2/3
posledela

Answer:

First angle = 117 degrees.

Second angle = 63 degrees.

Step-by-step explanation:

6 0
3 years ago
Use what you know about the angle sum theorem for triangles and your algebra skills to solve for x and find the measure of all t
melomori [17]

Answer:

2x° = 45°, 3x° = 67.5°

Step-by-step explanation:

Sum of angles in a triangle = 180°

2x+3x+3x=180°

8x=180°

x=22.5°

2x=22.5°x2=45°

3x=22.5°x3=67.5°

8 0
3 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

7 0
3 years ago
Read 2 more answers
M=p/n+4 make n the subject​
Kipish [7]

Answer:

n = \frac {p - 4m}{m}

Step-by-step explanation:

Given the algebraic expression;

m = \frac {p}{n + 4}

To make n the subject of formula.

Cross-multiplying, we have;

m*(n+4) = p

mn + 4m = p

Rearranging the equation, we have;

mn = p - 4m

n = \frac {p - 4m}{m}

6 0
3 years ago
Read 2 more answers
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