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Nookie1986 [14]
3 years ago
7

Two different ways to find the difference for 12-3

Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0
For this case we have:

 way 1:
 
Common factor 3 in the expression:
 12-3 = 3 (4-1)

12-3 = 3 (3)

12-3 = 3 (9)

 Way 2:
 
Write the number 12 as the sum of 4 times 3:
 12-3 = (3 + 3 + 3 + 3) - 3

 Then, for associative property:
 12-3 = 3 + 3 + 3 + (3 - 3)

12-3 = 3 + 3 + 3 + (0)

12-3 = 3 + 3 + 3

12-3 = 9
Scrat [10]3 years ago
7 0
12-3=9
9+3=12
12-9=3

I hope this helped!
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Answer:

undefined

Step-by-step explanation:

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Helga [31]

<h3>They are 268 miles far apart after 4 hours</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

<u>Given :</u>

v₁ = 30 mph due east

v₂ = 60 mph due south

t = 4 hours

<u>Unknown :</u>

displacement = d = ?

<u>Solution :</u>

d_1 = v_1 \times t

d_1 = 30 ~ mph \times 4 ~ h

d_1 = \boxed {120 ~ miles}

d_2 = v_2 \times t

d_2 = 60 ~ mph \times 4 ~ h

d_2 = \boxed {240 ~ miles}

d^2 = (d_1)^2 + (d_2)^2

d^2 = 120^2 + 240^2

d^2 = 72000

d = \sqrt{72000}

d = 120\sqrt{5} ~ miles

d \approx \boxed {268 ~ miles}

<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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The slope-intercept form: y = mx + b

m - slope

b - y-intercept

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----------------------------------------------------------------

y = 3/2 x - 3 it's the same function like first function.

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Step-by-step explanation:

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