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3 years ago

Solve for x: −2(x + 3) = −2x − 6 0 3 All real numbers No solution

Mathematics

2 answers:

Alik [6]3 years ago

8 0

Answer:

x ∈ All real numbers

Step-by-step explanation:

When the distributive property is applied to the left side, the parentheses can be eliminated and the equation becomes ...

-2x -6 = -2x -6

This is true for all possible values of x, "all real numbers".

Law Incorporation [45]3 years ago

5 0

Answer: All real solutions

Step-by-step explanation:

The given equation: $-2(x + 3) = -2x - 6$

Fist we open bracket on the right hand side , we get

$-2(x) + -2(3) = -2x - 6\\\\\Rightarrow\ -2x-6=-2x-6$

Adding 2x and 6 and on both sides , we get

$0=0$

Thus, the equation is true for all values of x.

Hence, solution for x= All real solutions

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Find the slope of (-2, 5) & (2, 13)<br><br> HELPPPOO

MrMuchimi

Answer:

The slope is 2.

Step-by-step explanation:

DIVIDE 13-5/2+2

That gives you 8/4 which equals 2.

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3 years ago

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Gemiola [76]

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3 years ago

Let x be the amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train. Suppose that the d

larisa [96]

Answer:

a) $P(X$

$P(X>14) = 1-P(X$

b) $P(7< X$

c) We want to find a value c who satisfy this condition:

$P(x$

And using the cumulative distribution function we have this:

$P(x$

And solving for c we got:

$c = 20*0.9 = 18$

Step-by-step explanation:

For this case we define the random variable X as he amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train, and we know that the distribution for X is given by:

$X \sim Unif (a=0, b =20)$

Part a

We want this probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a} = \frac{x-0}{20-0}= \frac{x}{20}$

And using the cumulative distribution function we got:

$P(X$

For the probability $P(X>14)$ if we use the cumulative distribution function and the complement rule we got:

$P(X>14) = 1-P(X$

Part b

We want this probability:

$P(7< X$

And using the cdf we got:

$P(7< X$

Part c

We want to find a value c who satisfy this condition:

$P(x$

And using the cumulative distribution function we have this:

$P(x$

And solving for c we got:

$c = 20*0.9 = 18$

3 0

3 years ago

Find u, v , u , v , and d(u, v) for the given inner product defined on Rn. u = (0, −4), v = (5, 3), u, v = 3u1v1 + u2v2

tigry1 [53]

Answer:

$=-12$

$d(u,v)=2\sqrt{31}$

Step-by-step explanation:

We are given that inner product defined on $R_n$

$=3u_1v_1+u_2v_2$

u=(0,-4),v=(5,3)

We have to find the value of <u,v> and d(u,v)

We have $u_1=0,u_2=-4,v_1=5,v_2=3$

Substitute the value then we get

$=3(0\cdot5)+(-4)(3)=-12$

Now, $d(u,v)=\left \|v-u\right \|$

Using this formula we get

$d(u,v)=\left \| (5,7) \right \|=\sqrt{3(5)^2+(7)^2}=\sqrt{75+49}=\sqrt{124}$

$d(u,v)=2\sqrt{31}$

7 0

3 years ago

Solve the equation. (enter your answers as a comma-separated list. round your answers to four decimal places.) x2e5x + 3xe5x − e

aleksley [76]

It's essential that you use " ^ " to indicate exponentiation if you want to communicate your ideas here accurately.

<span>x2e5x + 3xe5x − e5x = 0 should be written as

x^2e^(5x) + 3xe^(5x) - 1e^(5x) = 0.

e^(5x) can be factored out of all four terms, leaving us with

e^(5x) [x^2 + 3x - 1] = 0. e^(5x) is never zero, so no solution there.

However, we can set x^2 + 3x - 1 equal to zero and solve for x:

-3 plus or minus sqrt(3^2 - 4(1)(-1) )
x = ----------------------------------------------------
2
-3 plus or minus sqrt(13)
= ----------------------------------------
2

So the original equation has two roots.</span>

7 0

4 years ago