How do you know the wave is a mechanical wave?

Masja [62]

Answer:

The science or act of measuring changes in state variables of a body for the purpose of deriving the heat transfer associated with changes of its state due, for example, to chemical reactions, physical changes, or phase transitions under specified constraints.

Explanation:

5 0

4 years ago

The formation of CsCl from Cs(s) and Cl2 (g) involves the following steps:

scoray [572]

Explanation:

1) $Cs(s)\rightarrow Cs(g)$

Energy will be absorbed by the Cs(s) to get converted into Cs(g). In order to break the strong association of particles present in solid to convert it into gaseous state energy will be needed. So, energy will be absorbed by the Cs solid in this reaction.

2) $\frac{1}{2}Cl_2(g)\rightarrow Cl(g)$

Energy will be absorbed by $Cl_2$ gas in order to break bond between two Cl atoms to form isolated(alone) single chlorine atom.So, the energy will be absorbed by the chlorine gas molecule in this reaction.

3) $Cs(g)\rightarrow Cs^+(g)+e^-$

Energy will be absorbed by the Cs(g) to get converted into $Cs^+(g)$ cation. In order to remove an electron from the outer most shell of Cs atom energy will be required by Cs atom, So, energy will be absorbed in this reaction.

4) $Cl(g)+e^-\rightarrow Cl^-(g)$

Energy will get release in formation of $Cl^-$ anion from Cl atom in gaseous state. Chlorine atom need one electron to attain noble gas configuration. So, when an electron is added to the outer most shell of chlorine it attains stability of fully filled outermost shell by which it releases energy on addition of an electron.

5) $Cs^+(g)+Cl^-(g)\rightarrow CsCl(s)$

Energy will get release on formation of CsCl(s) from $Cs^+$ cation and $Cl^-$ anion. since both are oppositely charged ion and due to strong electrostatic interaction will get converted into stable molecule of CsCl (s) with release in an energy.

6 0

3 years ago

using the soubility curve what is the solubilityof nh4cl in 10 mL of water at a temperature of 60 degrees Celsius

lukranit [14]

Answer:

Please, see attached two figures:

The first figure shows the solutility curves for several soluts in water, which is needed to answer the question.

The second figure shows the reading of the solutiblity of NH₄Cl at a temperature of 60°C.

Answer: 5.5g

Explanation:

The red arrow on the second attachement shows how you must go vertically from the temperature of 60ºC on the horizontal axis, up to intersecting curve for the solubility of NH₄Cl.

From there, you must move horizontally to the left (green arrow) to reach the vertical axis and read the solubility: the reading is about in the middle of the marks for 50 and 60 grams of solute per 100 grams of water: that is 55 grams of grams of solute per 100 grams of water.

Assuming density 1.0 g/mol for water, 10 mL of water is:

$10mL\times 1.0g/mL=10g$

Thus, the solutibily is:

$10gWater\times 55gNH_4Cl/100gWater=5.5gNH_4Cl$

5 0

4 years ago

Two answer multiple-choice-- please help!

Troyanec [42]

Answer:

A spray of perfume diffusing in a room is a spontaneous process because gas particles have higher entropy when they are spread evenly around the room.

This is true because entropy increase when gas particles spread

Explanation:

6 0

3 years ago

An electron in an atom is known to be in a state with magnetic quantum number ml=0. What is the smallest possible value of the p

rusak2 [61]

Answer:

1

Explanation:

The principal quantum number, n, showsthe principal electron shell. which can inturn be describe as the most probable distance of the electrons from the nucleus, the larger the number n is, the farther the electron is from the nucleus, the larger the size of the orbital, and the larger the atom is. n can be any positive integer starting at 1, as n=1 designates the first principal shell (the innermost shell). When an electron is in an excited state or it gains energy, it may jump to the second principle shell, where n=2

As the energy of the electron increases, so does the principal quantum number, e.g., n = 3 indicates the third principal shell, n = 4 indicates the fourth principal shell, and so on. n=1,2,3,4…

On the other hand, the magnetic quantum number ml determines the number of orbitals and their orientation within a subshell. Consequently, its value depends on the orbital angular momentum quantum number l. Given a certain l, ml is an interval ranging from –l to +l, so it can be zero, a negative integer, or a positive integer. ml=−l,(−l+1),(−l+2),…,−2,−1,0,1,2,…(l–1),(l–2),+l

note also that: The orbital angular momentum quantum number l determines the shape of an orbital, and therefore the angular distribution. The number of angular nodes is equal to the value of the angular momentum quantum number l. Each value of l indicates a specific s, p, d, f subshell (each unique in shape.) The value of l is dependent on the principal quantum number n. Unlike n, the value of l can be zero. It can also be a positive integer, but it cannot be larger than one less than the principal quantum number (n-1): l=0,1,2,3,4…,(n−1).

So the answer is 1

3 0

4 years ago