Answer:
Mass = 141.6 g
Explanation:
Given data:
Mass of Kr in gram = ?
Volume in L = 9.59 L
Temperature = 46.0°C
Pressure = 4.62 atm
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
46.0+273 = 319 K
4.62 atm × 9.59 L = n× 0.0821 atm.L/ mol.K ×319 K
44.3 atm.L = n×26.19 atm.L/ mol
n = 44.3 atm.L / 26.19 atm.L/ mol
n = 1.69 mol
Mass in gram:
Mass = number of moles × molar mass
Mass = 1.69 mol × 83.79 g/mol
Mass = 141.6 g
Answer:
12
Explanation:
If GT bisects BN at point G, then point G would be in the middle of BN. So, since Bg and NG have to be equal and add up to 24, then the answer is 12.
First, we have to calculate the number of moles of H2SO4 in the solution:
V=60 mL = 0.06 L
c=5.85 mol/L
n=V×c=0.06×5.85=0.351 mol
Then we need to find the molar mass of H2SO4:
2×Ar(H) + Ar(S) + 4×Ar(O) =
=2 + 32 + 64 = 98 g/mol
Finally, we need to find the mass of H2SO4:
m=0.351 × 98 = 34.398 g
Answer:
The answer to your question is 0.33 moles of H₃PO₄
Explanation:
Data
moles of Ca(OH)₂ = 0.050
moles of H₃PO₄ = ?
Process
1.- Write the balanced chemical equation
3Ca(OH)₂ + 2H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6H₂O
Reactants Elements Products
3 Ca 3
12 H 12
14 O 14
2.- Calculate the moles of phosphoric acid
3 moles of calcium hydroxide --------------- 2 moles of phosphoric acid
0.5 moles of calcium hydroxide ----------- x
x = (0.5 x 2)/3
x = 0.33 moles
The freezing point of water in Celsius is 0 degrees and the boiling point is 100 degrees so the answer would be 100 degrees
