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Novay_Z [31]
2 years ago
10

The temperature of a sample of water increases from 20.9°C to 45.5°C as it absorbs 5637 J of heat. What is the mass of the sampl

e?
Chemistry
1 answer:
djyliett [7]2 years ago
4 0
Q = 5637 J

 C =4.814 J/KgºC

Temperature  : 45.5ºC - 20.9º C = 24.6ºC

Q = m x C  x T

5637 = m x 4.814 x 24.6

5637 = m x 118.4244

m = 5637 / 118.4244

m = 47.60 g

hope this helps!
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A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume
alexandr402 [8]

Answer:

x_{N_2F_2}= 0.415\\\\x_{SF_6}=0.585

Explanation:

Hello!

In this case, since the mole fraction of both gases in the tank is computed via:

x_{N_2F_2}=\frac{n_{N_2F_2}}{n_{N_2F_2}+n_{SF_6}} \\\\x_{SF_6}=\frac{n_{SF_6}}{n_{N_2F_2}+n_{SF_6}}

It means we need to compute the moles of each gas, just as it is shown down below:

n_{N_2F_2}}=5.53gN_2F_2*\frac{1molN_2F_2}{66.01gN_2F_2} =0.0838molN_2F_2\\\\n_{SF_6}=17.3gSF_6*\frac{1molSF_6}{146.06gSF_6} =0.118molSF_6

Thus, the mole fractions turn out:

x_{N_2F_2}=\frac{0.0838mol}{0.0838mol+0.118mol}= 0.415\\\\x_{SF_6}=\frac{0.0838mol}{0.0838mol+0.0838mol}=0.585

Best regards!

8 0
2 years ago
You have 1.6 x10 21 atoms of oxygen, what is the mass of that number of atoms
iren [92.7K]

Answer: 166.023×1023

Explanation:

Mass of 6.023×1023 atoms of oxygen = gram atomic mass of oxygen.

Mass of 6.023×1023 atoms of oxygen = 16g

∴ Mass of 1 atom of oxygen =166.023×1023

6 0
3 years ago
Explain why a coin is able float on top of the water
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Whats the difference between conduction, convection, radiation, biosphere, and geosphere
jonny [76]
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8 0
3 years ago
Consider the following gas samples: 10. g of hydrogen gas, 10. g of helium gas, 2.5 moles of nitrogen gas, 110. g of carbon diox
Pepsi [2]

Explanation:

As we know ,

One mole of a gas contains 6.023 * 10 ²³ number of atoms .

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,  

n = w / m

n = moles ,  

w = given mass ,  

m = molecular mass .

( a ) From the question ,

w = 10 g ,

As we know molecular mass of Hydrogen = 2 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 / 2 = 5 mol

The number of atoms in one molecule of Hydrogen = 2

Hence ,

The number of atoms = 5 * 2 *  6.023 * 10 ²³ = 60.23 * 10 ²³ atoms .

( b )  From the question ,

w = 10 g

As we know molecular mass of helium gas = 4 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 10 /4 = 2.5 mol

The number of atoms in one molecule of Helium = 1

Hence ,

The number of atoms = 5 * 1 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( c ) From the question ,

moles of nitrogen gas = 2.5 mol

The number of atoms in one molecule of  nitrogen gas = 2

Hence ,

The number of atoms = 2.5 * 2 *  6.023 * 10 ²³ = 30.115 * 10 ²³ atoms .

( d ) From the question ,

w = 110 g

As we know molecular mass of carbon dioxide gas = 44 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  = 110 / 44 = 2.5 mol

The number of atoms in one molecule of  carbon dioxide = 3

Hence ,

The number of atoms = 2.5 * 3 *  6.023 * 10 ²³ = 45.17 * 10 ²³ atoms .

( e )

From the question ,

w = 365 g

As we know molecular mass of  sulfur hexafluoride gas = 146 g/mol

Using the above formula , and putting the respective values ,

Moles = n ,

n = w / m  =  365 / 146 = 2.5 mol .

The number of atoms in one molecule of sulfur hexafluoride gas = 7

Hence ,

The number of atoms = 2.5 * 7 *  6.023 * 10 ²³ = 105.40 * 10 ²³ atoms .

Hence ,

The order is -

sulfur hexafluoride > Hydrogen > carbon dioxide  > nitrogen gas = helium gas

4 0
3 years ago
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