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3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics

2 answers:

Galina-37 [17]3 years ago

5 0

Answer:

The probability is 0%.

Step-by-step explanation:

The reason is 3 is the only number greater than 2, so if 3 was already drawn, then there are no other cards higher than 2.

harina [27]3 years ago

3 0

Answer:

Step-by-step explanation:

Cards: 1,2,3 total cards 3

P (3) = number of 3's / total cards

= 1/3

We keep the 3

Cards: 1,2 total cards 2

We want a card greater than 2

cards greater than 2 : 0

P (card >2) = cards greater than 2 / total cards

=0/2

P (3, no replacement, >2) = 1/3 * 0 =0

You might be interested in

The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

4 0

3 years ago

PLEASE HELP <br> Show work

dsp73

Answer:

$\tan(24) = \frac{x}{13} \\ 0.445228685308 \times 13 = x \\ x = 5.787972909010 \\ x = 5.788$

$\tan(68) = \frac{27}{x} \\2.475086853416 \times x = 27 \\ x = 27 \div 2.475086853416 \\ x = 10.90870809754 \\ x = 10.909$

$\tan(0) = \frac{5}{12 } \\ \tan(0) = 0.41666663066666 \\ 0 = {76}^{0} 30$

3 0

3 years ago

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

3 years ago

Jon and Ed are discussing their cell phone plan for text messaging. Jon pays $20 a month for his phone and $0.15 per text messag

aliina [53]

Answer: 200 texts

explanation:
use y = mx + b
y = cost of phone bill
m = price per text
x = # of texts
b = price of phone for the month

jon’s bill: y = .15x + 20
ed’s bill: y = .10x + 30

set them equal to each other bc you want to find how many texts for their bill to be equal

.15x + 20 = .10x + 30 (subtract .10x and 20 from both sides)
.05x = 10
x = 200 texts

7 0

3 years ago

Find the recursive formula.<br> 8, 12, 16, 20, ...

ArbitrLikvidat [17]

First term, a
1

=4
Second term, a
2

=8
Common difference, d=a
2

=a
1

d=8−4=4
∴ The common difference is 4

7 0

3 years ago