For a), wouldn't you multiply the cost of a twin by the quantity of a twin beige (N) and the cost of a queen by the quantity of the queen beige (N) and then the cost of the king by the quantity of the king beige (N) for CN and do the same thing but with the south quantities?
And then for b), it's just comparing which one had the most money and find the difference...
And then C), would be relatively self explanatory where CN would be the potential profit in N and CS would be the potential profit in S and then CN+CS would be the potential profit total?
By adding the 1st and third equation together, you get rid of z and end with 7x+8y=13. The second equation will be the second equation and 2 times the first equation, so the will yield 3x+8y=1. Now, you solve this system of equations and get x3, y=-1, and z=-4
There is an X intercept at x=-8
There is a y intercept at y=4 (0,4)