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amm1812
3 years ago
13

In London, half of the days have some rain. The weather forecaster is correct 2/3 of thetime, i.e., the probability that it rain

s, given that she has predicted rain, and the probabilitythat it does not rain, given that she has predicted that it won’t rain, are both equal to 2/3.When rain is forecast, Mr. Pickwick takes his umbrella. When rain is not forecast, he takesit with probability 1/3. Find (a) the probability that Pickwick has no umbrella, given that itrains. (b) the probability that it doesn’t rain, given that he brings his umbrella.
Mathematics
2 answers:
Tema [17]3 years ago
7 0

Answer:

The other person is right

Step-by-step explanation:

Mnenie [13.5K]3 years ago
3 0

Answer:

(a) The probability that Pickwick has no umbrella, given that it rains is 2/9

(b) The probability that it doesn’t rain, given that he brings his umbrella is 5/9

Step-by-step explanation:

(a) The probability that Pickwick has no umbrella, given that it rains: P1

P1 = P (rain) * P (not umbrella)

This probability have two components, if rain forecasts or not rain forecasts:

  1. When rain is forecast Mr. Pickwick takes his umbrella, so the probability of not umbrella is zero and the probability of rain for a rain forecast is 2/3 (the weather forecaster is correct 2/3 of the time)
  2. When not rain forecast, he takes it with probability 1/3, so the probability of not takes it is 2/3 and the probability of rain with a not rain forecast is 1/3 (the weather forecaster is correct 2/3 of the time, so there is 1/3 probability of rain)

P1 = 2/3*0 + 1/3*2/3 = 0 + 2/9 = 2/9

The probability that Pickwick has no umbrella, given that it rains is 2/9

(b) The probability that it doesn’t rain, given that he brings his umbrella: P2

P2 = P (not rain) * P (umbrella)

This probability have two components, if rain forecasts or not rain forecasts:

  1. When rain is forecast Mr. Pickwick takes his umbrella, so the probability is one and the probability of rain for a rain forecast is 2/3, so the probability of rain is 1/3  (the weather forecaster is correct 2/3 of the time, so 1/3 will be wrong)
  2. When not rain forecast, he takes it with probability 1/3 and the probability of not rain with a not rain forecast is 2/3 (the weather forecaster is correct 2/3 of the time)

P1 = 1/3*1 + 2/3*1/3 = 1/3 + 2/9 = 5/9

The probability that it doesn’t rain, given that he brings his umbrella is 5/9

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b)  95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data  a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14  

sample standard deviation 'S' = 9.3

<u>95 percent confidence interval for this single-sample t test</u>

The values are (x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })  the <u>95 percent confidence interval for the population mean  'μ'</u>

Degrees of freedom γ=n-1=62-1=61

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(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })

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[(11.64 , 16.36]

<u>Conclusion:-</u>

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

<u></u>

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3 years ago
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Step-by-step explanation:

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Answer:

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