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qwelly [4]
2 years ago
8

A rectangular wall has length 3 less than 4 times the width . I wish to put a silver line along the corners of the wall. The lin

ing costs 25 cents per foot and I spent a total of $18.50 for the lining on the corners of the wall. If painting costs 20 cents per square foot , how much dose it cost to paint the wall? PLEASE ANSWER correctly. I WILL GIVE BRAINLIEST ANSWER TO U IF U DO
Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
4 0

Answer:

Step-by-step explanation:

Let width = w units

Length = 4w - 3

Cost for lining corners of wall = $ 18.50

Perimeter of the wall = 18.50/0.25 =  74 ft

2*(length  +width ) = 74

2*(4w - 3 + w) =74

2*(5w - 3) =74

10w - 6 = 74   {Add 6 to both sides}

10w - 6 + 6 = 74 + 6

10w = 80

Divide both sides by 10

10w/10 = 80/10

w =  8 ft

Length = 4w - 3 = 4*8 - 3 = 32 - 3

Length = 29 ft

Area of the wall = length * width

                           = 29 * 8

                           =  232 square ft

Cost of painting the wall per square feet = 20 cents = 0.20

Cost of painting 232 square feet = 232 * 0.20

                                                             = $ 46.40

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Donald bought 3 shirts for $45. How many shirts can Donald buy if he has $30? Show your work using mathematics.
horsena [70]

Answer:

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4 0
2 years ago
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The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the expect
Liula [17]

Answer:

After 25 years the population will be:

  • Australia: 22271200
  • China: 1580220878
  • Mexico: 157380127
  • Zaire: 112794819

Step-by-step explanation:

Growth rate problem that has a growth rate proportional to the population size can be solved using the equation:

 P(t) = P₀eʳᵗ

  • t is your unit of time. It could be days, or hours, or minutes. It changes depending on each problem. In this problem, t is measured in years because you're jumping from 2000 to 2025. Years just makes the most sense to measure that leap in time.
  • P(t) is the population at time t. An example in this problem could be P(20) would be the population 20 years after the initial count. or maybe P(12) would be the population 12 years after the initial count. or P(0) would be the initial count of the population.
  • P₀ is the initial population at P(0)
  • r is the growth rate.<u><em> Don't forget to convert the percentage to its decimal form</em></u>

Now that everything is set out, lets use the equation to solve for our answer.

P(t) = P₀eʳᵗ

<u>Australia:</u>

P(t)=(19169000)e^{(0.006)t}

after 25 years

P(25)=(19169000)e^{(0.006)(25)}=22271200.6

<u>China:</u>

P(t) = (1261832000)e^{(.009)t}

after 25 years:

P(25)=(1261832000)e^{(.009)(25)}=1580220878

<u>Mexico:</u>

P(t) = (100350000)e^{(0.018)t}

after 25 years:

P(25)=(100350000)e^{(0.018)(25)}=157380127.8

<u>Zaire:</u>

P(t) = (51965000)e^{(0.031)t}

after 25 years:

P(25)=(51965000)e^{(0.031)(25)}=112794819.9

6 0
3 years ago
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Answer:

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RULE:

WHEN MULTIPLYING TWO NEGATIVES YOU WILL GET POSITIVE.

IF ONE IS NEGATIVE AND THE OTHER IS POSITIVE WHEN MULTIPLYING IT WILL BE NEGATIVE.

WHEN MULTIPLYING TWO POSITIVE NUMBERS IT WILL ALWAYS BE POSITIVE

SAME THING IF YOU MULTIPLY A POSITIVE NUMBER WITH A NEGATIVE NUMBER YOU GET A NEGATIVE AS YOUR ANSWER

YOU NEED ONE SIGN OF THE SAME WHEN MULTIPLYING TO BE A POSITIVE AS YOUR ANSWER

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3 years ago
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