The mountains can and will block airflow from higher pressure systems that come in from a coast and won't combine to nake storms
Answer:
d=1.07m
Explanation:
Calculate Initial Kinetic Energy:
KE = 1/2*m*v^2
KE= 0.5*(10.3kg)*(1.64m/s)^2 = 13.85J
Calculate work overcoming friction:
W = F*d = mu*m*g*d
W = (0.128)*(10.3kg)*9.80m/s^2)*d
W = 12.92*d
Equate the two since all of the kinetic energy is used up in working against friction:
W = KE
12.92d = 13.851J
Solve for d:
d= (13.851J)/(12.92) = 1.07 m
Answer:
option c
Explanation:
Kinetic energy is due to the speed of a body.

When speed is doubled, the kinetic energy is quadruple.
From third equation of motion, braking distance is also proportional to square of speed. Thus, when speed is doubled, the braking distance is quadruple.
Thus, option c is correct.
Answer:
The distance between the object is 
Explanation:
The free body diagram of this setup is on the first uploaded image
From the question
The diameter of closely packed cones in the fovea of the eye is = 
The distance of separation by one cone(not excited ) is
The distance between the two point-like object is l
The diameter of the eye is D = 2 cm
The distance of the two point-like object from the near point of the eye is A = 28 cm
From the diagram we see that the light from the two point-like object form a triangle of similar base l and d and height D and A
So for a triangle with similar base we have that


making l the subject we have


Answer:
A shorter than the original source and in the researcher's words
Explanation:
The summary is an abridged version of the original source and in the researcher's own very words.
Summaries gives an over-arching perspective and excludes implicit details from a given text.
A summary should not be detailed and must avoid overt illustrations. They must capture the true essence of piece leaving out flowery details.
A summary should be lesser in length than the original piece. Any third party reader should immediately be able to grab the details of the original piece from the summary.