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ira [324]
3 years ago
8

Not yet answered Points out of 2.00 Not flaggedFlag question Question text Two cars collide head-on on a level friction-free roa

d. The collision was completely inelastic and both cars quickly came to rest during the collision. What is true about the velocity of this system's center of mass?
Physics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

Velocity of center of mass must be ZERO

Explanation:

As we know that two cars are moving on friction-less surface

So here we can say that on the system of cars there is no external force along x direction

So we can say that

F_{net} = \frac{dP_{cm}}{dt}

so here if net force is zero

\frac{dP_{cm}}{dt} = 0

P_{cm} = constant

since finally the two cars comes to rest so here final velocity of center of mass of two cars will be zero and hence it will be always zero as there is no force on the system of two cars

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Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
butalik [34]

Answer:

a) I = -2257.6 Kg*m/s

b) F = -451,520N

Explanation:

part a.

we know that:

I = P_f-P_i

where I is the impulse, P_f the final momentum and P_i the initial momentum.

so:

I = MV_f-MV_i

where M is the mass, V_f the final velocity and V_i the initial velocity.

Therefore, we have to find the initial velocity or the velocity of the passenger just before the collition.

now, we will use the law of the conservation of energy:

E_i=E_f

so:

mgh = \frac{1}{2}MV_i^2

where g is the gravity and h the altitude. So, replacing values, we get:

(85kg)(9.8m/s^2)(36m)= \frac{1}{2}(85kg)V_i^2

solving for V_i:

V_i = 26.56m/s

Then, replacing in the initial equation:

I = MV_f-MV_i

I = (85kg)(0m/s)-(85kg)(26.56m/s)

I = -2257.6 Kg*m/s

Then, the impulse is -2257.6 Kg*m/s, it is negative because it is upwards.

part b.

we know that:

Ft = I

where F is the average force, t is the time and I is the impulse. So, replacing values, we get:

F(0,005s) = -2257.6 Kg*m/s

solving for F:

F = -451520N

Finally, the force is -451,520N, it is negative because it is upwards.

3 0
3 years ago
How much is the tension number 2
mestny [16]

This is what I got:

Net force in the Y direction:

ΣFy = T1 - T2

F = ma

ma = T1 - T2

Isolate for T2

ma - T1 = -T2

Multiply by -1

T1 - ma = T2

100 - (3)(2) = T2

100 - 6 = T2

T2 = 94 N

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Short Answer Questions:
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According to Archimede's principle, a physical object experiences an upthrust due to a difference in pressure between upper and lower  surfaces.

<h3>What is an upthrust?</h3>

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Based on scientific information, a physical object experiences an upthrust when it is immersed in a fluid due to a difference in height and pressure between upper (top) and lower (bottom) surfaces.

According to Archimede's principle, there is a higher pressure at the bottom of the physical object due to height, and a lower pressure at the top of the physical object.

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