mass of the box = 20 kg
force of friction on the box due to surface



similarly kinetic friction on it



now the weight of the suspended block will be

so here the weight of the suspended block is less than the limiting friction on it
So here we will say that friction will counter balance the weight of the suspended block and it will not move at all
So acceleration of the box will be zero
Answer:
Team A has the greatest momentum
Explanation:
The momentum of an object is a vector quantity given by

where
m is the mass of the object
v is its velocity
In this problem, we have to compare the momenta of the different sleds.
We have:
A) Sled Team A 48 kg moving at 10m/s:
m = 48 kg
v = 10 m/s
p = (48)(10) = 480 kg m/s
B) Sled Team B 14 kg moving at 18m/s
m = 14 kg
v = 18 m/s
p = (14)(18) = 252 kg m/s
C) Sled Team C 28 kg moving at 12m/s
m = 28 kg
v = 12 m/s
p = (28)(12) = 336 kg m/s
D) Sled Team D 22 kg moving at 12m/s
m = 22 kg
v = 12 m/s
p = (22)(12) = 264 kg m/s
So, team A has the greatest momentum.