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2 years ago

6

An airplane accelerat s down a runway at 3.20 m/s(squared) for 32.8s until is finally lifts off the ground. Presume to he plane

starts from the rest. Determine the distance traveled before takeoff.
The answer is 1721.3 but I want to know how to get it

1 answer:

rusak2 [61]2 years ago

5 0

SORRRY not this smart

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2 years ago

5. Three children are at work. One is pushing a chair, another is pushing the sofa and the third one is pushing an empty trolley

katen-ka-za [31]

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sofa

Explanation:

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3 years ago

If it takes 100 N to get a 10 kg object to accelerate at 10m/s/s, how much force will it take to get a 20 kg object to accelerat

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Answer: C) 200 N

Explanation:

The force $F$ is defined as:

$F=m.a$

Where:

$m=20 kg$ is the mass of the object

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Then:

$F=(20 kg)(10 m/s^{2})$

Finally:

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Hence, the correct option is C.

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3 years ago

A person who normally weighs 580 N is riding in an elevator that is moving upward, but slowing down at a steady rate. If this pe

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Answer:

M au = Fs - M g au = upwards acceleration; Fs = scale reading

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If the acceleration is zero Fs = M g and the scale reads the persons weight

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1 year ago

the car starts from a stop to travel 1100 meters in 14 seconds. it is clocked at 65 m/s at point k. find its average speed and a

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Answer:

The average velocity of the car is, V = 74.04 m/s

Explanation:

Given data,

The initial velocity of the car, u = 0 m/s

The displacement of the ca, S = 1100 m

The time period of travel, t = 14 s

The velocity of the car at point k, v = 65 m/s

Using the II equation of motion,

S = ut + ½ at²

Substituting the given values,

1100 = 0 + ½ x a x 14²

a = 11.22 m/s²

Using the III equation of motion

v² = u² + 2 as

v = √(2as) (∵ u = 0)

Substituting,

v = √(2 x 11.22 x 1100)

= 157.11 m/s

The average speed of the car,

$V=\frac{0+65+157.11}{3}$

V = 74.04 m/s

Hence, the average velocity of the car is, V = 74.04 m/s

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2 years ago