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bazaltina [42]
2 years ago
8

Select the correct answer.

Computers and Technology
1 answer:
Serga [27]2 years ago
6 0

B: feasibility study

They are analyzing whether the project or application makes sense or is feasible, given the available resources, budget and projected monetary gains.

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Which of these is NOT one of the main parts of an email?
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I think the answer is c
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2 years ago
Which one of the following terms is defined as the material and surfaces upon which an artist works?1. Applied arts2. Context3.
babunello [35]

Answer:

The correct answer to the following question will be Option D (Media).

Explanation:

Media are the contact channels or devices used to store information or data and distribute it. The phrase refers to elements of the media marketing industry such as printed media, printing, mainstream media, film, theater, television and radio broadcast, and advertisement.

There are mainly three types of media, which are as follows:

  • Print media
  • Broadcast media
  • Internet

Using these three media, we can describe the content and the surfaces on which an artist works.

Therefore, Option D is the right answer.

5 0
3 years ago
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
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