3 years ago

A model rocket is launched into the air from ground level.

Mathematics

1 answer:

Anon25 [30]3 years ago

8 0

$p(x)=-16x^2+32x

p(x)=0
$

$-16x^2+32x = 0$

$-16x(x-2)=0$

$x_1=0, x_2=2$

Rocket will be in the air for 2 seconds.

You might be interested in

Carson can choose one vehicle (car or truck), one color (blue, red, or silver), and one type of transmission (standard or automa

77julia77 [94]

Answer:

12 possible outcomes

Step-by-step explanation:

Choosing 1 vehicle from 2 = 2C1 = 2

Choosing 1 color from 3 = 3C1 = 3

Choosing 1 type from 2 = 2C1 = 2

Number of possible outcomes :

2C1 * 3C1 * 2C1

2 * 3 * 2

= 12 different possible outcomes

5 0

3 years ago

I need help with this please it’s some this about diameter idk

lianna [129]

120 cubic feet I think

7 0

3 years ago

Read 2 more answers

The cost of renting a boat is $51 for 5 hours. Which of the following is not an equivalent rate? Give the letter of your answer

alexgriva [62]

B. Obviously all the numbers have to do with one and it’s 30. If it’s wrong let me know !

4 0

3 years ago

F(x)=(5x+3)(x−2)(3x+7)(x+5) has zeros at x = -5, x = -7/3, x = 2

musickatia [10]

The sign of f on the interval -7/3 < x < -3/5 is always positive.

<h3>How to solve for the sign on the interval</h3>

We have the equation

(5x+3)(x−2)(3x+7)(x+5) > 0

Now when f(x) > 0

Then -7/3 < x < -3/5

This would tell us that the sign would become positive when it changes from the less than to greater than sign

<h3>Complete Question</h3>

f(x)=(5x+3)(x-2)(3x+7)(x+5) has zeros at x=-5, x=-7/3, x=-3/5, and x=2

What is the sign of f on the interval -7/3<x<-3/5?

answer choices

f is always positive on the interval

f is always negative on the interval

f is sometimes positive and sometimes negative on the interval

f is never positive or negative on the interval