I think your answer is qt
Answer:
the equation to finding slope is this:
y2-y1 / x2-x1
Where y2 is the y value of the second point, y1 is the y value of the first point, x2 is the value of the second x value, and x1 is the x value of the first point.
5-0 / -2-2
5/-4
-5/4 is the slope
Step-by-step explanation:
Answer:
8w^2 I don't know why it is not on here, but I put it in an algebra calculator and everything. Good luck. :)
Step-by-step explanation:
Simply the radicals by multiplying and taking square roots.
2
*
= 2
*2w![\sqrt[4]{2w}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2w%7D)
= 4w![\sqrt[4]{16w^4}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16w%5E4%7D)
=4w(2w)
=
Answer:
d.
Step-by-step explanation:
The red graph is the black one times 2.
So y = 2 f(x). which is the same as y/2 = f(x) (divide by 2).
Given:
The x and y axis are tangent to a circle with radius 3 units.
To find:
The standard form of the circle.
Solution:
It is given that the radius of the circle is 3 units and x and y axis are tangent to the circle.
We know that the radius of the circle are perpendicular to the tangent at the point of tangency.
It means center of the circle is 3 units from the y-axis and 3 units from the x-axis. So, the center of the circle is (3,3).
The standard form of a circle is:

Where, (h,k) is the center of the circle and r is the radius of the circle.
Putting
, we get


Therefore, the standard form of the given circle is
.