HOW MANY TENTHS IN 100!!!!!!! PLEASE

Jason needed to get his computer fixed. He took it to the repair store. The technician

tatiyna

Answer:

<u>55 dollars per hour</u>

Step-by-step explanation:

419.25 - 103 = 316.25

316.25 ÷ 5.75 = 55

$55 per hour

hope this helps

7 0

3 years ago

ASAP please <br> Like I need answers now <br> I’m so confused

GuDViN [60]

Answer: 143.75 yd

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Sam is in charge of food supplies for a camp this summer. The 7-day camp will be attended by 30 children. In a previous cam, 275

Sophie [7]

Answer:

Sam should order 480.9 ≈ 481 pounds so that there is enough food for the 7-day camp this summer

Step-by-step explanation:

Given :

The 7-day camp will be attended by 30 children.

In a previous cam, 275 pounds of food were served to 24 children over 5 days

To Find: How many pounds of food should Sam order so that there is enough food for the 7-day camp this summer?

Solution :

24 children served food for 5 days = 275 pounds

24 children served for 1 day = $\frac{275}{5}$

1 children served for 1 day = $\frac{275}{5*24}$

= 2.29 pounds

So, 30 children served for 1 day = 2.29*30 = 68.7 pounds

So, 30 children served for 7 days = 68.7*7 = 480.9 pounds

Hence, Sam should order 480.9 ≈ 481 pounds so that there is enough food for the 7-day camp this summer

3 0

3 years ago

Are two consecutive integers in which the square root of -6

GuDViN [60]

Answer:

3 and 4

Step-by-step explanation:

1^2 = 1

2^2 = 4

3^2 = 9

4^2 = 16

Since 15 is between 9 and 16, the square root of 15 is between 3 and 4

3 0

4 years ago

A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious

Dominik [7]

Answer:

Part1) $z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191$

$p_v =2*P(Z>2.191)=0.0284$

Readjustment is needed

Part 2) $z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

$z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

$p_v =2*P(Z$

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1

$\bar X=16.32$ represent the sample mean

$\sigma=0.8$ represent the population standard deviation

$n=30$ sample size

$\mu_o =16$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a two tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu =16$

Alternative hypothesis : $\mu \neq 16$

Compute the test statistic

The statistic for this case is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(Z>2.191)=0.0284$

Using the value of $\alpha =0.05$ we see that $pv$ and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

$(-\infty ;-1.96) , (1.96;\infty)$

Part 2

$\bar X=15.82$ represent the sample mean

We can replace in formula (1) the info given like this:

$z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232$

Give the appropriate conclusion for the test

Since is a two tailed test the p value would be:

$p_v =2*P(Z$

Using the value of $\alpha =0.05$ we see that $pv>\alpha$ and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

$(-\infty ;-1.96) , (1.96;\infty)$

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

5 0

4 years ago