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kolbaska11 [484]
4 years ago
8

A program gives computers to families with schools with middle-aged children. They have a certain number of computers to distrib

ute fairly between several families. How many computers should each family get? 1. One month the program has 8 computers. The families have these numbers of school-aged children: 4,2,6,2,2.
Mathematics
1 answer:
zhannawk [14.2K]4 years ago
6 0

Answer:

\text{2, 1, 3, 1, 1}

Step-by-step explanation:

\text{There are a total of 8 computers and 16 school-aged children,} \\\text{therefore there must be 2 children per computer.}\\\frac{16}{8}=2 \text{ (As shown)}\\\text{The families each with 4, 2, 6, 2, 2 children should get;}\\\text{2, 1, 3, 1, 1 computers respectively.}

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Answer:

15 girls

Step-by-step explanation:

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Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0
Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} +11x+15=0  

so

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substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{121-120}} {4}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1}{4}=-2.5

x_2=\frac{-11(-)1}{4}=-3

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3 years ago
PLEASE HELP FREE 15 POINTS
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Answer:

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