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Yuri [45]
3 years ago
8

A poll shows that 41% of voters in a city favor of a $0.0.1 tax increase. If 25 voters are selected at random, what is that exac

tly 15 of them will vote in favor of the initiative?
Mathematics
1 answer:
juin [17]3 years ago
5 0

Answer:

The probability is 0.026 to 3 d.p

Step-by-step explanation:

To calculate this , we shall be using the Bernoulli approximation.

let P = percentage of voters supporting the increase = 41% = 41/100 = 0.41

q = percentage of voters not supporting = 100-41% = 59% = 59/100 = 0.59

Now we want to calculate that exactly 15 out of 25 will vote in favor

Mathematically that would be ;

25C15 p^15 q^10

= 25C15 0.41^15 0.59^10

= 0.025981307443 or simply 0.026 to 3 decimal places

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1) n(a) = 5


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The union of two set is a set composed by all the elements belonging to either one of the sets, with no repetitions. So, since the first set contains all numbers from 1 to 5, the second set contains a 4, which however already belonged to the first set, but also a 6, which is added in the union. So, a ⋃ c = {1,2,3,4,5,6}, and thus n(a ⋃ c)=6.


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4 0
3 years ago
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#11
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