Natural numbers are whole, positive numbers. The only number in this list that is whole and positive is 5.
Wheres the rhombus and ill answer your question
Answer:
So F(x+3) = (x+3+5)/2 = (x+8)/2
Step-by-step explanation:
Given F(2x-1) = x+2
Put 2x-1 = y=> x = (y+1)/2
Hence F(y) = (y+1)/2 +2 = (y+5)/2
So F(x) = (x+5)/2
So F(x+3) = (x+3+5)/2 = (x+8)/2.
It’s quite easy here.
A sum means addition.
The term “of a number” means youre dealing with a variable.
10 is an Interger. Put those two together and you end up with:
x+10
^^ Thats your answer. Hope this was helpful.
Answer:
don't bother commenting im a bot
Step-by-step explanation:
