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3 years ago

I need to know how to solve 7/20=

1 answer:

6 0

First off, you can use your calculator.

7 / 20 = 7 divided by 20

You can multiply both top and bottom by 5.

This is to make the bottom 100.

(7*5) / (20*5)

35 / 100

0.35

7/20 = 0.35

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Graph the proportional relationship, y = 5x.

kap26 [50]

Answer:

Hope the graph below helps.

Step-by-step explanation:

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3 years ago

Which does NOT show a reasonable estimate for 673 × 18?

Yakvenalex [24]

Answer:

A. 14,000

Step-by-step explanation:

because 673 rounded would equal 700

and 18 rounded would be 20

so 700x20 would be 14,000

hopefully you understand

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6 0

3 years ago

Are O, N, and P collinear? If so, name the line on which they lie.

san4es73 [151]

We are given a figure where M, N , O and P points are given.

We need to explain if points O, N, and P collinear or not.

Note: All co-linear points are in a straight line.

From the figure, we can see that <em>O and N points are in a straight line but point P is aside.</em>

So, the points O, N, and P are not collinear.

Therefore, correct option is "<u>No, the three points are not collinear</u>".

7 0

3 years ago

Please help with math problem give 5 star if do

Juliette [100K]

Answer:

C : -6

Step-by-step explanation:

Please Mark Me Brainliest!

4 0

2 years ago

Read 2 more answers

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

4 years ago

Read 2 more answers