Question

The function f(x) = 2x2 + 6x - 12 has a domain consisting of the integers from -2 to 1, inclusive. Which set represents the corresponding range values for f(x)?

Answer 1

Answer:

[-16,-4]

Step-by-step explanation:

We are given that

$f(x)=2x^2+6x-12$

Domain=[-2,1]

We have to find the set of range values of f(x).

Substitute x=-2

$f(-2)=2(-2)^2+6(-2)-12$

$f(-2)=-16$

Substitute x=1

$f(1)=2(1)+6(1)-12=-4$

Range of f(x)=[-16,-4]

Hence, the set of range values of f(x)

[-16,-4]