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zzz [600]
3 years ago
14

EXPERTS/ACE/GENIUS (and people that wanna actually help)

Physics
2 answers:
scZoUnD [109]3 years ago
8 0
Hello! Force = mass * acceleration. We can go ahead and eliminate A and B, because those answers are too small. We can multiply 4.5 (mass) * 9 (acceleration) to find the amount of force needed. 4.5 * 9 is 40.5.The amount of force needed is 40.5 N. The answer is C: 40.5 N.
erma4kov [3.2K]3 years ago
3 0
I just took the test and the answer was C. 40.5n. hope this helps everyone who was looking for this answer

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A hollow conducting sphere with an outer radius of 0.295 m and an inner radius of 0.200 m has a uniform surface charge density o
IrinaK [193]

Answer:

a. 6.032\times10^{-6}C/m^2

b.6.816\times10^5N/C

Explanation:

#Apply  surface charge density, electric field, and Gauss law to solve:

a. Surface charge density is defined as charge per area denoted as \sigma

\sigma=\frac{Q}{4\pi r_{out}^2}, and the strength of the electric field outside the sphere E=\frac{\sigma _{new}}{\epsilon _o}

Using Gauss Law, total electric flux out of a closed surface is equal to the total charge enclosed divided by the permittivity.

\phi=\frac{Q_{enclosed}}{\epsilon_o}\\\\\sigma=\frac{Q}{4\pi r_{out}^2}\\\\\sigma=\frac{0.370\times 10^{-6}}{4\pi \times (0.295m)^2}\\\\=3.383\times10^{-7}C/m^2  #surface charge outside sphere.

\sigma_{new}=\sigma_{s}-\sigma\\\\\sigma_{new}=6.37\times10^{-6}C/m^2-3.383\times10^{-7}C/m^2\\\\\sigma_{new}=6.032\times10^{-6}C/m^2

Hence, the new charge density on the outside of the sphere is 6.032\times10^{-6}C/m^2

b. The strength of the electric field just outside the sphere is calculated as:

From a above, we know the new surface charge to be 6.032\times10^{-6}C/m^2,

E=\frac{\sigma _{new}}{\epsilon _o}\\\\=\frac{6.032\times10^{-6}C/m^2}{\epsilon _o}\\\\\epsilon _o=8.85\times10^{-12}C^2/N.m^2\\\\E=\frac{6.032\times10^{-6}C/m^2}{8.85\times10^{-12}C^2/N.m^2}\\\\E=6.816\times10^5N/C

Hence, the strength of the electric field just outside the sphere is 6.816\times10^5N/C

5 0
3 years ago
A ground-fault circuit interrupter is a (an) _____.
Arada [10]
The answer is A, A ground fault circuit interrupted monitors the amount of electricity in a circuit and if there is any leakage or an interruption of current it cuts the power to avoid a shock your welcome :)
7 0
4 years ago
Read 2 more answers
If I Throw a bowling ball and a tennis ball from a building, describe if one would hit the ground first and why.
olga nikolaevna [1]

Answer:

The bowling ball would

Explanation:

Because it contains more weight! And that will make it fall down quicker.

Hope it helped

3 0
3 years ago
Which selection is a characteristic of both living and nonliving things
prisoha [69]
Theyre both made of cells
5 0
3 years ago
Design an inverting amplifier that has a gain of -47 (this gain is negative). Pick resistor values that you have in the lab kit.
Nostrana [21]

Answer:

R2= 470 ohms R1= 10ohms. Schematic is attached

Explanation:

Av=-(R2/R1)

-47=-(470/10)

-47=-47

7 0
3 years ago
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