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Pavel [41]
3 years ago
10

The air inside a balloon exerts a force of 1.5 n on an area of 0.5 m^2. what is the pressure inside the balloon?

Physics
2 answers:
maxonik [38]3 years ago
4 0
Pressure=force/area
1.5/0.5=3Pa
Tresset [83]3 years ago
3 0

Lesson 9: Fluid Pressure (connexus students!)

1.D) 3 n/m^2

2.C) 2 meters below the surface of a swimming pool

3.B) cork

4.A) depends only on the type of fluid

5.A) the air pressure decreases

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PLEASE HELP ME ASAP!!!!!!! <br> giving brainliest for correct answers
Vera_Pavlovna [14]

Answer:

b

Explanation:

6 0
3 years ago
What Is a Sound Wave? Learning Goal: To understand the nature of a sound wave, including its properties: frequency wavelength, l
NISA [10]

Answer:

A)  Propagation of pressure fluctuations in a medium

B) air is the medium in which the wave is transported,

Explanation:

Part A.

A sound wave is a longitudinal oscillation of the molecules that forms in a material medium, they can be solid, liquid or gases, therefore the wave propagates in the same direction as the oscillation of the particles.

The most correct answer is:

* Propagation of pressure fluctuations in a medium

Part b

air is the medium in which the wave is transported, otherwise it cannot propagate

8 0
3 years ago
A4 kg bowling ball begins rolling down a at bowling alloy at 6 m/s . When it strikes the pins, it is estimated to be moving at 5
Paul [167]

Answer:

Energy lost due to friction is 22 J      

Explanation:

Mass of the ball m = 4 kg

Initially velocity of ball v = 6 m/sec

So kinetic energy of the ball KE=\frac{1}{2}mv^2

KE=\frac{1}{2}\times 4\times 6^2=72J

Now due to friction velocity decreases to 5 m/sec

Kinetic energy become

KE=\frac{1}{2}\times 4\times 5^2=50J

Therefore energy lost due to friction = 72 -50 = 22 J

8 0
3 years ago
what is the mass of a cannon ball if a force 2500 N gives the cannon ball an acceleration of 200 m/s squared?
nignag [31]

Using Newton's second law of motion:

F=ma ;  [ F = force (N: kgm/s^2);m= mass (kg); a = acceleration (m/s^2)


Given:                      Find:                   Formula:                  Solve for m:

F: 2500N                 mass:?                F=ma Eq.1              m=F/a  Eq. 2

a= 200m/s^2  


Solution:

Using Eq.2

m= (2500 kgm/s^2)/ (200m/s^2) = 12.5 kg

8 0
3 years ago
A 2500-lb vehicle has a drag coefficient of 0.35 and a frontal area of 20 ft2. What is the minimum tractive effort required for
emmasim [6.3K]

Answer:

i put this in the calculator and my answer is 600. hope this helps

Explanation:

4 0
3 years ago
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