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Tasya [4]
3 years ago
14

Do tessellations have to be polygons?

Mathematics
1 answer:
den301095 [7]3 years ago
8 0
Its the last one, the shapes but be polygons.
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What is the answer to > solve 4cos (theta/3) -2 = 0, over [0, 4pi)
Vesna [10]

Hello from MrBillDoesMath!

Answer:  

@ =   pi/3 (or 60 degrees) or @ = 7 pi/3 (or 420 degrees)


Discussion:

Let "@' denote the angle "theta". We are asked to find @ in the interval [0, 4 pi)

where

4cos(@) - 2 = 0.                Adding 2 to both sides

4 cos(@) - 2 +2 = 2  =>

4 cos(@) = 2                     Divide both sides by 4

cos(@) = 2/4 = 0.5


This implies that @ =   pi/3 (or 60 degrees) or @ = (pi/3 + 2pi) = 7 pi/3 (or 420 degrees)


Thank you,

MrB

5 0
3 years ago
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7 0
3 years ago
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Which value for the number makes the statement true?
umka21 [38]
A product is the result of multiplication.
A quotient is the result of division.
So you're trying to find the quotient of a number (x) and 5 that equals 8.

Try plugging in the answers. 
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A. x=4
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B. x=8
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C. x=40
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D. x=80
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So your answer is C. 40
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3 0
3 years ago
What is f(5) for the function f(x)=2x+8?
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Just subtitute 5 as x in the equation given for f.
2(5)+8=18.
3 0
2 years ago
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