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lbvjy [14]
3 years ago
14

Is -27 greater then |-14|

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer: No


Step-by-step explanation:

Because the absolute value of -14 is 14


skelet666 [1.2K]3 years ago
3 0

Answer:

No

Step-by-step explanation:

the absolute value function always returns a positive value. The value inside the bars can be positive or negative but the result is always positive

| - 14 | = 14 > - 27


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If one endpoint of a line segment is (2, 8) and the midpoint is (-4, 7), what is the other endpoint? (8, -5)
Pepsi [2]

( - 10, - 22 )

using the midpoint formula,

let the other endpoint have coordinates (x, y) then

\frac{1}{2} (2 + x ) = - 4 ( multiply through by 2 )

2 + x = - 8 ( subtract 2 from both sides ) then

x = -8 - 2 = - 10 ← value of x-coordinate

Similarly for y-coordinate

\frac{1}{2} (8 + y ) = - 7 ( multiply through by 2 )

8 + y = - 14 ( subtract 8 from both sides )

y = - 14 - 8 = - 22 ← y -coordinate

the other endpoint is ( - 10, - 22 )




7 0
3 years ago
How do you simplify negative exponents
tangare [24]
Multiply (or distribute) the exponent<span> outside the parenthesis with every </span>exponent<span>inside the parenthesis, remember that if there is no </span>exponent<span> shown, then the </span>exponent<span> is 1. Step 3: Apply the </span>Negative Exponent<span> Rule. </span>Negative exponents<span> in the numerator get moved to the denominator and become positive </span>exponents<span>.</span>
3 0
3 years ago
Please answer this for me pleaseeeee
kobusy [5.1K]

Answer:

\Huge\boxed{x=71.9}

Step-by-step explanation:

Hello There!

Once again we are going to use trigonometry to solve for x

Here are the <u>Trigonometric Ratios</u>

sin = opposite divided by hypotenuse

cos = adjacent divided by hypotenuse

tan = opposite divided by adjacent

we need to find x and we are given its opposite side length (58) and the adjacent side length (19)

this corresponds with tangent so once again we will be using tangent to solve for x

Looking at tangent we see that its equal to opposite divided by adjacent so we create an equation

tan(x)=\frac{58}{19}\\\frac{58}{19} =3.052631579

now we have

tan(x)=3.052631579

Once again we need to get rid of the tan

to do so we take the inverse of tan ( tan^-1) and apply it to each side

arcsin^-^1(tan(x))=x\\arcsin^-^1(3.052631579)=71.86191784

finally we round to the nearest tenth

we're left with x = 71.9

4 0
3 years ago
Latasha bought a concert ticket. She does not remember the price of the ticket, but she remembers that she had to pay $1 in tax.
docker41 [41]

Answer:

Original price of ticket = $12.5

Step-by-step explanation:

Given:

8% amount = $1

Find:

Original price of ticket

Computation:

Original price of ticket = 1(100/8)

Original price of ticket = $12.5

7 0
3 years ago
A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg
polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

P(X = x) = nCx p^{x} q^{n - x}

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662

Finally, the probability that 2 or fewer students will withdraw is

P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355

b) Compute the probability that exactly 4 will withdraw.

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0
3 years ago
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