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kolezko [41]
3 years ago
14

The work in a office takes 150 hours to complete every week

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0
You would need at least 5 people in the office.
150/32=4.6, but you cannot have 1/6 of a person so you would need to round up to 5 people.
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I'd love some help on this question. I do not understand how you would go about working this out, so please explain the working
zhannawk [14.2K]
Area = length x width and volume = length x width x height soo you would have to multiple 4 and 25 and that’s 100
7 0
2 years ago
Tickets to the concert were 2.50 for adults and 1.00 for students. 1,200 was collected and 750 tickets were sold.
Minchanka [31]

Answer:

I'm assuming you want to know the amount of child and adult tickets sold. 450 student tickets were sol, and 300 adult tickets.

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

3 0
3 years ago
The following table shows the number of hours some high school students in two states spend surfing the Internet each week:
babymother [125]
1st data set:

Minimum: 34
1st quartile: 35
Median: 36
3rd quartile: 37
Maximum: 38

Second data set:
Minimum: 20
1st quartile: 23
Median: 25
3rd quartile: 38
Maximum: 65

Graph it based on the values of the 1st and 3rd quartile. If they are both the same number away from the mean then they are symmetrical. Otherwise they are not. In this case, the first one is similar and the second one is not.

Please mark as brainiest!
Cheers
7 0
3 years ago
Prove that√P is irrational for any prime number P​
Luda [366]

Answer:

Step-by-step explanation:

I’m not sure if this is super accurate, but since P is prime, the only factors it has is 1 and itself, meaning that the square root of it will be irrational

3 0
3 years ago
What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
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