3 are expected to have the condition.
The expected value is the found by multiplying the probability by the number in the sample:
(1/200)×600
= (1/200)×(600/1)
= (1×600)/(200×1)
= 600/200 = 3
16x+60y
16(.75)+60(.25)
12+15=27
maria would charge $27 for this necklace
Answer:
the common difference is 6.
Step-by-step explanation:
Given;
first term of an AP, a = -7
let the common difference = d
The third term is written as;
T₃ = a + 2d
The eight term is written as;
T₈ = a + 7d
The ratio of the eight term to third term = 7:1

Therefore, the common difference is 6.
K=2.35. You are correct.
Have a nice day! :)