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Paha777 [63]
3 years ago
10

Solve for u in terms of r, s, and t. t= –rsu u=

Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

u = - \frac{t}{rs}

Step-by-step explanation:

Given

t = - rsu ( multiply both sides by - 1 )

- t = rsu ( divide both sides by rs )

- \frac{t}{rs} = u

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3 years ago
Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.
Andreas93 [3]

Answer:  k = {8, -8}

<u>Step-by-step explanation:</u>

In order for a quadratic equation to have exactly one solution, the discriminant must equal zero.       →        b² - 4ac = 0

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  ↓       ↓      ↓

a=4    b=k    c=4

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3 years ago
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RoseWind [281]

Answer:

Step-by-step explanation:

hello :

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8 0
3 years ago
What is the following quotient? StartFraction RootIndex 3 StartRoot 60 EndRoot Over RootIndex 3 StartRoot 20 EndRoot EndFraction
FrozenT [24]

Answer:

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Step-by-step explanation:

We are required to simplify the quotient: \dfrac{\sqrt[3]{60} }{\sqrt[3]{20}}

Since the <u>numerator and denominator both have the same root index</u>, we can therefore say:

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6 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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3 years ago
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