Answer:

Step-by-step explanation:
<u>Solving Equations Using Successive Approximations</u>
We need to find the solution to the equation

where


The approximation has been already started and reached a state for x=2.5 where


The difference between the results is 0.25, we need further steps to reach a good solution (to the nearest tenth)
Let's test for x=2.4


The new difference is -0.2+0.24=0.04
It's accurate enough, thus the solution is

The answer is 15 foot 7 inches or 187 inches.
The first equation given 
We have to add 1 and 5 to the right side first. We will get,

To get rid of 6 from the right side we have to subtract 6 from both sides.



To find n we have to move -2 to the other side by dividing both side by -2.



So we have got the required answer for the first question.
The solution is n = 0.
The second equation given,

First we have to move 7x to the left side by subtracting it from both sides.



Now we have to move -2 to the right side by adding 2 to both sides.



We have got the required answer for the second question.
The solution is x = -7.
The third equation given,

We have to get rid of that negative sign from both sides. As we have negative sign to both sides we can cancel it out. We will get,

Now we have to move 4 to left side by subtracting it from both sides.




So we have got the required answer .
The solution is x = 4.
The answer is B. A reflection across the x-axis.
Answer:
The minimum score that such a student can obtain and still qualify for admission at the college = 660.1
Step-by-step explanation:
This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the
Mean = μ = 560
Standard deviation = σ = 260
A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?
Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.
P(x > x') = P(z > z') = 35% = 0.35
P(z > z') = 1 - P(z ≤ z') = 0.35
P(z ≤ z') = 1 - 0.35 = 0.65
Using the normal distribution table,
z' = 0.385
we then convert this z-score back to a combined math and verbal scores.
The z-score for any value is the value minus the mean then divided by the standard deviation.
z' = (x' - μ)/σ
0.385 = (x' - 560)/260
x' = (0.385×260) + 560 = 660.1
Hope this Helps!!!