First divide the coefficients:-
-18 / -12 = 3/2
a^-2 / a^-4 = a^2
b^-5 / b^-6 = b
so the expression simplifies to 3a^2b / 2
We have been given that a right △ABC is inscribed in circle k(O, r).
m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.
First of all, we will draw a diagram that represent the given scenario.
We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.
We will use sine to find side AB.
![\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}](https://tex.z-dn.net/?f=%5Ctext%7Bsin%7D%3D%5Cfrac%7B%5Ctext%7BOpposite%7D%7D%7B%5Ctext%7BHypotenuse%7D%7D)
![\text{sin}(30^{\circ})=\frac{AC}{AB}](https://tex.z-dn.net/?f=%5Ctext%7Bsin%7D%2830%5E%7B%5Ccirc%7D%29%3D%5Cfrac%7BAC%7D%7BAB%7D)
![\text{sin}(30^{\circ})=\frac{18}{AB}](https://tex.z-dn.net/?f=%5Ctext%7Bsin%7D%2830%5E%7B%5Ccirc%7D%29%3D%5Cfrac%7B18%7D%7BAB%7D)
![AB=\frac{18}{\text{sin}(30^{\circ})}](https://tex.z-dn.net/?f=AB%3D%5Cfrac%7B18%7D%7B%5Ctext%7Bsin%7D%2830%5E%7B%5Ccirc%7D%29%7D)
![AB=\frac{18}{0.5}](https://tex.z-dn.net/?f=AB%3D%5Cfrac%7B18%7D%7B0.5%7D)
![AB=36](https://tex.z-dn.net/?f=AB%3D36)
Wee know that radius is half the diameter, so radius of given circle would be half of the 36 that is
.
Therefore, the radius of given circle would be 18 cm.
Answer:
24
Step-by-step explanation:
In a fraction, the top number is the numerator and the bottom number is the denominator.