Answer:
95%
Step-by-step explanation:
Given that in a large class, students' grade in a test followed the normal distribution.
The normal distribution is symmetric about the mean, bell shaped and having area of more than 99% between 3 std deviations from the mean on either side.
We are to find the percent of grades is between two standeard deviation below the mean and two standar deviation above the mean (that is in between Xbar-2S and Xbar+2S grades)
where x bar is the mean and s = std devition
This is equivalent to 100*Prob that X lies between these two values
As per normal distribution curve 68, 95, 99 rule we get
approximately 95% lie between these two values.
Answer:
a)
P(X = 0) = 5/10
P(X = 5) = 3/10
P(X = 10) = 2/10
b)
E = 0·5/10 + 5·3/10 + 10·2/10 = 3.5
V = 0^2·5/10 + 5^2·3/10 + 10^2·2/10 - 3.5^2 = 15.25
Answer:
f
Step-by-step explanation:
Answer:
w = -16
Step-by-step explanation:
w + (-2) = -18
Add 2 to each side
w-2+2 = -18+2
w = -16
Answer:
{x,y} = {3,1}
Step-by-step explanation:
visit this for more info;
https://www.tiger-algebra.com/drill/2x_y=7;x-y=2/
