What is the greatest common factor of 30, 45, and 35?

Mathematics

2 answers:

Gnom [1K]3 years ago

6 0

Answer:

The prime factors of 30 are 2 x 3 x 5. The prime factors they have in common are 3 x 5. 3 x 5 = 15. The greatest common factor is 15

The greatest common factor of 35 and 15 is 5. The 'greatest common factor' is sometimes called the 'GCF.

Greatest Common Factor (GCF) of two numbers

the factors of 40 are 1, 2, 4, 5, 8, 10, 20 and 40, and the factors of 50 are 1, 2, 5, 10, 25 and 50.

Step-by-step explanation:

Bess [88]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

What is (+5) - (-1) - (-3)

maksim [4K]

+ = positive
Positive and positive makes a positive

Negative and negative makes a positive

- = negative
Negative and positive makes a negative

Positive and negative makes a negative

Your answer: +5 - (-1) = 6
+6 - (-3) = +9
Your answer that youre looking for is: 9

4 0

3 years ago

Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown

guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

$P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) = (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001$