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Ipatiy [6.2K]
3 years ago
6

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

after 10 days and 20 days, respectively?
Mathematics
1 answer:
boyakko [2]3 years ago
6 0

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

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Step-by-step explanation:

Here, p represents cost of one potato and n represents the cost of one onion.

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Putting the values of n from 2) in equation 1),

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Step-by-step explanation:

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Geometry
Kobotan [32]

Answer: UV = 52

Concept:

Additive property of length, or the segment addition postulate, states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

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<u>Given information</u>

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<u />

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Hope this helps!! :)

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Step-by-step explanation:

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