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Ipatiy [6.2K]
3 years ago
6

Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have

after 10 days and 20 days, respectively?
Mathematics
1 answer:
boyakko [2]3 years ago
6 0

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

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3 years ago
HELP: Will Award Brainliest! Simplify 17x - 12 = 114 + 3x
mrs_skeptik [129]

Answer:

x=9

Step-by-step explanation:

17x - 12 = 114 + 3x

First  Subtract 3x from both sides

14x - 12 = 114

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4 years ago
Katherine invested $86,000 in an account paying an interest rate of 52%
earnstyle [38]

Answer: $4,331‬

Step-by-step explanation:

I will assume that the question meant 5.2% not 52% as this is quite excessive.

Katherine after 13 years.

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r = 5.2% = 5.2/365 = 5.2/365%

Future value = P * ( 1 + r)^n

= 86,000 * (1 + 5.2/365%)⁴⁷⁴⁵

= $169,068

Michael after 13 years;

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Future value = Pe^rt

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= $164,737

Difference = 169,068 - 164,737

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