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Hitman42 [59]
2 years ago
11

The 14 question pls answer fast !!!

Mathematics
1 answer:
Dvinal [7]2 years ago
5 0

Answer:

1.C

2.D

3.A

4.B

5.D

6.A

Step-by-step explanation:

this is an answer...keep safe

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What is the volume of the composite figure? Round your answer to the nearest hundredth. Use 3.14 for π.
Reil [10]

Answer:

<em><u>263.76</u></em><em><u> </u></em><em><u>in</u></em><em><u>^</u></em><em><u>3</u></em>

VOLUME OF FIGURE=VOL.OF CONE+VOL.OF CYLINDER +VOL.OF HEMISPHERE

=(1/3×3.14×3×3×4)+(3.14×3×3×6)+(2/3×3.14×3×3×3)

=37.68+169.56+56.52

=263.76in^3

7 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0
3 years ago
How to multiply 15 by 13
Mkey [24]
15 multiplied by 13 is equal to 195.
4 0
3 years ago
Read 2 more answers
Eeeeeeeeeeeeeeeeeeeee
11111nata11111 [884]

Answer:

I think the answer is 42

Step-by-step explanation:

So, with all of that, the equation will now be = 5^2 + (2 * 8) / 2 + (3 * 3)

So next, you can use PEMDAS. After that, u should get ur answer of 42.

Work:

5^2 + (2 * 8) / 2 + (3 * 3)

5^2 + 16 / 2 + 9

25 + 16 / 2 + 9

25 + 8 + 9

25 + 17

= 42

Hope this helps :D!!

3 0
2 years ago
Read 2 more answers
What’s equal to 2/32
defon

Answer:

1/16 4/64

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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