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IrinaK [193]
3 years ago
11

2x + y = 5 , x + y = 4Solve the system of linear equations.

Mathematics
1 answer:
kumpel [21]3 years ago
8 0

2x+y=5

x+y=4


We need to solve 2x+y=5 for y

let's start by adding -2x to both sides

2x+y-2x=5-2x

y=-2x+5

Now substitute -2x+5 for y in x+y=4

x+y=4

x-2x+5=4

-x+5 =4

Add -5 to both sides so we can find the value for x

-x+5-5=4-5

-x=-1

We know that x can not stay with the negative sign so to eliminate that we need to divide both sides by -1

-x/-1= -1/-1

x=1

Now we have the value for x :)

We need to find the value for y by substitute 1 for x in y=-2x+5

y=-2x+5

y= (-2)(1)+5

y= -2+5

y= 3

Final answer : x=1 and y=3

                          (1,3)


I hope that's help :)

Please let me know by rating my answer and a Thanks :0

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Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

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Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

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Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

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