Asa has 15 dimes and 32 quarters.
Step-by-step explanation:
Given,
Total coins = 47
Worth of coins = $9.50 = 9.50*100 = 950 cents
1 dime = 10 cents
1 quarter = 25 cents
Let,
Number of dimes = x
Number of quarters = y
According to given statement;
x+y=47 Eqn 1
10x+25y=950 Eqn 2
Multiplying Eqn 1 by 10

Subtracting Eqn 3 from Eqn 2

Dividing both sides by 15

Putting y=32 in Eqn 1

Asa has 15 dimes and 32 quarters.
Keywords: linear equation, elimination method
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Answer:
-2x+5y should be the answer
hope that helps
I don’t know if that’s what you wanted but I hope I helped ;D (sorry for my bad english)
139, 149, 159, 169, 179, 189, 199, 209, 219, 229, 239, 249, 259.
The common difference is 13.
Let n = 52
Let d = common difference
a_52 = 139 + (52 - 1)(13)
a_52 = 139 + (51)(13)
a_52 = 139 + 663
a_52 = 802