Please help:

1 answer:

5 0

7 7/9 clergs.
wergs= w
nergs= n
clergs= c

3w= 4n, so 5w= 6 2/3n
Since 6n=7c, then 6 2/3n= 7 7/9n

Hope that answered your question!!

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A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of

lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean x = 31,5

Sample standard deviation s₂ = 8,35

Sample size n₂ = 11

Ti-84 Calculator

Sample mean y = 46,2

Sample standard deviation s₁ = 9,99

Sample size n₁ = 12

t(s) = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s) = 12,9 / √(99,8/12) + (69,72/11)

t(s) = 12,9 / √8,32 + 6,34

t(s) = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis H₀ y - x > 1,80

Altenative Hypothesis Hₐ y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c) critical value for

t(c) α; n₁ +n₂-2 df = 12 +11 -2 df = 21

If we choose CI = 95 % then α = 5 % α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0

3 years ago

The equation y=2.54x gives the length y in centimeters corresponding to a length x in inches. What is the length in centimeters

bija089 [108]

The equation given in the question is
y = 2.54 x
In this equation, x is in cm and y is in inches
Size of the ruler = 1 foot
= 12 inches.
Putting the value of 12 inches in the equation, we get
y = 2.54x
= 2.54 * 12
= 30.48 cm
From the above deduction, we can conclude that the length of the ruler is 30.48 cm. I hope that this is answer that you were looking for and the answer has come to your desired help.

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3 years ago

Guys please help! In triangle CDE, the measure of angle C is 90 degrees, side CD is 15 and DE is 3 more than CE. Find the length

AURORKA [14]

You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)

your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°

-> insert those values, with c substituted with b+3 to remove c

c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE

DE=CE+3=36+3=39

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3 years ago

The volume of water in a tank is modeled by the function y = 1.15x3 – 0.1x2 + 2 where x is the number of minutes after the fauce

Thepotemich [5.8K]

Given:

The volume of water in a tank is modeled by the function

$y=1.15x^3-0.1x^2+2$