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11Alexandr11 [23.1K]
3 years ago
10

Name each angle in four ways.

Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

Answer:1obtuse ghi h igh 2.acute rqp prq q 3.complementary 4.sorry it’s not visible but if the angle is flat which I asume it’s supplementary

Step-by-step explanation:

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Answer:

The area is 10 square units

Step-by-step explanation:

A = 1/2bh

A = 1/2(4)(5)

A = 10 square units

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Find the four arithmetic means between 100 and 135. Show work.
Masteriza [31]

Answer:

Please read the answers below.

Step-by-step explanation:

Let's calculate the four means between 100 and 135, this way:

1. Arithmetic mean:

(100 + 135)/2 = 117.5

2. Weighted mean:

We will assign equal weight to both numbers : 5

(100 * 5 + 135 * 5)/10 = (500 + 675)/10 = 1,175/10 = 117.5

3. Geometric mean:

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4. Harmonic mean:

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Which inequality describes the number of levels, l, you can play in 60 minutes?<br> Choose 1 answer
Paul [167]

Answer:

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3 years ago
Wendell’s dog, Jordan, was getting in his way as he worked in the backyard. So, Wendell chained him to a pole. If the chain is 1
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What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

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4 years ago
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