Question

What is the equation of the graphed line written in standard form?

Answer 1

First of all, standard form means it should be this form ax+by=c
The equation for the line is
y= 1/4x-1========>Multiply each term by 4
y (4) = 1/4(4)x-1(4)
4y = 4/4x-4
4y=x-4=========>Subtract x from both sides
4y-x=x-x-4

4y-x=-4 OR X-4Y=4
Your answer is A.

Answer 2

we know that

The equation of the line in standard form is equal to

$Ax+By=C$

where

A is a positive integer

B and C are integers

Step 1

Find the slope of the graphed line

we have

$A(0,-1)\ B(4,0)$

The slope of the line is equal to

$m=\frac{y2-y1}{x2-x1}$

Substitute the values

$m=\frac{0+1}{4-0}$

$m=\frac{1}{4}$

Step 2

Find the equation of the line in slope-intercept form

the equation of the line in slope-intercept form is equal to

$y=mx+b$

where

m is the slope

b is the value of the y-intercept

In this problem we have

$m=\frac{1}{4}$

$b=-1$ ------> see the graph

substitute

$y=\frac{1}{4}x-1$

Step 3

Convert to standard form

Multiply by $4$ both sides

$4y=x-4$

$x-4y=4$

therefore

the answer is the option

$x-4y=4$