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Natali [406]
3 years ago
5

Can angles that measure 60, 60 and 60 degrees form exactly one triangle, more than one triangle or no triangle? Why?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

Yes, a 60,60,60 angle triangle equals 180

Step-by-step explanation:

Every triangle has to equal 180 degrees or it's not a triangle at all. This forms 1 triangle.

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Is this set of ordered pairs a function ? (1,9) (0,8) (3,0) (4,9) (7,7).
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Answer:

It is not a function because the output of 9 repeats.

(1,9) (4,9)

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Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

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fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

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Graph W only. But be careful it is not directly proporotional.

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