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klemol [59]
3 years ago
5

HELP PLEASE ILL GIVE BRAINLISTTTT!!!

Mathematics
1 answer:
Ber [7]3 years ago
8 0

Answer:

Ok I’ll give a simple equation that your teacher probably won’t accept and one that your teacher will accept

Teacher accept: x-45=122

Not accept but way easier: 122+45=x

ALSO The answer to x: 167

Step-by-step explanation:

Heres the loop hole, they asked for 2 sentences but never declared the length of each sentence.

Explanation:

So we know that grace lost 45 pounds and at the end she weighs 122.

We don’t now what the beginning weight so we can make an equation like x-45=122 where x represents her before weight and the subtract 45 is when she lost that much and the final results of 122, if solved You’ll get her begginisng weight, 167.

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Answer:

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Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

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Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

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E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

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