Answer:
If f(1)=0 then 1 is a root and (x-1) is a factor of f(x). divide f(x) by (x-1). you now have a quadratic. Find its roots by methods you know.
actually this factors by grouping:
f(x)=x³+3x²-x-3
= x²(x+3)-1(x+3)
=(x+3)(x²-1)
=(x+3)(x-1)(x+1) // difference of squares
By zero product property roots are
-3, -1, 1
The solution of the equation is 3.
Okay I don’t think I have to do it anymore I
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Step-by-step explanation:
Step-by-step explanation:
<em>(-2)-(+15)=(-17)</em>
<em>the</em><em> </em><em>diffe</em><em>rence</em><em> </em><em>between</em><em> </em><em>those</em><em> </em><em>two</em><em> </em><em>temp</em><em>erature</em><em> </em><em>s</em><em> </em><em>is</em><em> </em><em>(</em><em>-</em><em>1</em><em>7</em><em>)</em>
