All categories

3 years ago

Brainliest 5 stars Thanks! Use the Remainder Theorem.

Mathematics

1 answer:

GalinKa [24]3 years ago

5 0

Answer:

If f(1)=0 then 1 is a root and (x-1) is a factor of f(x). divide f(x) by (x-1). you now have a quadratic. Find its roots by methods you know.

actually this factors by grouping:

f(x)=x³+3x²-x-3

= x²(x+3)-1(x+3)

=(x+3)(x²-1)

=(x+3)(x-1)(x+1) // difference of squares

By zero product property roots are

-3, -1, 1

You might be interested in

Fine each angle measure to the nearest degrees.<br> Sin W=0.7771

monitta

Answer:

51 deg

Step-by-step explanation:

Sin W=0.7771

$W = sin^{-1} 0.7771$ (use calculator)

W = 50.996 deg

= 51 deg (to nearest degree)

3 0

3 years ago

Solve for xxx. Enter the solutions from least to greatest. (x -7)(-4x -2)=0(x−7)(−4x−2)=0left parenthesis, x, minus, 7, right pa

Lady bird [3.3K]

Answer:

-1/2, 7

Step-by-step explanation:

Given the expression

(x -7)(-4x -2)=0

This means that;

x - 7 = 0 and -4x - 2 = 0

x = 0+7 snd -4x = 2

x = 7 and x = -2/4

x = 7 and -1/2

Hence the solution from least to greatest is -1/2, 7

6 0

3 years ago

Are 7/18 and -21/-56 are equivalent

kap26 [50]

Answer:

yes they are equivalent. if you simplify -21/-56 by dividing it by 3 you will get -7/-21 which equals to 7/21

6 0

3 years ago

In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv

ycow [4]

Answer:

• David

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

• David's House, B(15,13)

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Owen's distance from school (AC)

$\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}$

David's distance from school (BC)

$\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}$

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0

1 year ago

Convert 6 kilometers to yards

NISA [10]

1 km=1093.61yards

6 km= 6*1093.61yards
6 km= 6561.66yards

Answer= 6561.66 yards

7 0

4 years ago