Answer:
D.
Step-by-step explanation:
Find the average rate of change of each given function over the interval [-2, 2]]:
✔️ Average rate of change of m(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, m(a) = -12
b = 2, m(b) = 4
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = 4
✔️ Average rate of change of n(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, n(a) = -6
b = 2, n(b) = 6
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = 3
✔️ Average rate of change of q(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, q(a) = -4
b = 2, q(b) = -12
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = -2
✔️ Average rate of change of p(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, p(a) = 12
b = 2, p(b) = -4
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = -4
The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]
1400kg.
Force=ma
2100N= m*1.5
2100/1.5= 1400kg.
Please mark me brainliest :)
Answer:
C
Step-by-step explanation:
There is a common ratio between consecutive terms
r = 24 ÷ 16 = 36 ÷ 24 = 54 ÷ 36 = 1.5 = 
This indicates the sequence is geometric with nth term ( explicit formula )
f(n) = a₁
where a₁ is the first term and r the common ratio
Here a₁ = 16 and r =
, then
f(n) = 16
→ C
Answer:
904.78 m³
Step-by-step explanation:
V = 4/3 × π r³ = 4/3 × π × 6³ = 904.78
Answer:
In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
Also:
The normal distribution is symmetric, which means that 50% of the data is above the mean and 50% is below.
Then:
In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.