Perimeter of a rectangle is given by (2 × Length(l)) + (2 × Width(w)) = 2l + 2w
l= 11 feet
2(11) + 2w = 46
2w = 46 - 22 = 24
w = 24/2 = 12 feet
Width = 12 feet.
V= 3.14r^2h
10/2= r
5^2= 25
(3.14)(25)(6)
V=471
We are given with the rectangle shaped deck which has a width of 29 feet and a perimeter of 134 feet. the perimeter of a rectangle is equal to twice the sum of length and width. hence the equation goes :
134 ≤ 2* (29 + L)
67 <span>≤ 29 + L
38 </span><span>≤ L
length should be greater or less than 38 feet</span>
Is their any multiple questions
